You add 3.00 g of Pb(NO3)2 (M.W. = 331.2 g/mole) to 75.0 mL of 0.100 M HCl, leading to formation of 0.873 g PbCl2 (M.W. = 278.1 g/mole) as a precipitate.

a) Which molecule is the limiting reactant?

 

b) What is the percent yield of PbCl2?